15x^2=29x+14=0

Solution for 15x^2=29x+14=0 equation:

15x^2=29x+14=0

We move all terms to the left:

15x^2-(29x+14)=0

We get rid of parentheses

15x^2-29x-14=0

a = 15; b = -29; c = -14;
Δ = b2-4ac
Δ = -292-4·15·(-14)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-41}{2*15}=\frac{-12}{30}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+41}{2*15}=\frac{70}{30}
=2+1/3
$